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Function dmd.func.FuncDeclaration.leastAsSpecialized
Determine partial specialization order of 'this' vs g. This is very similar to TemplateDeclaration::leastAsSpecialized().
final extern(C++) MATCH leastAsSpecialized
(
FuncDeclaration g,
dmd
);
Returns
match 'this' is at least as specialized as g 0 g is more specialized than 'this'
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