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Function std.array.replaceInto
Replace occurrences of from with to in subject in a new
array. If sink is defined, then output the new array into
sink.
void replaceInto(E, Sink, R1, R2)
(
Sink sink,
E[] subject,
R1 from,
R2 to
)
if (isOutputRange!(Sink, E) && isDynamicArray!(E[]) && isForwardRange!R1 && isForwardRange!R2 && (hasLength!R2 || isSomeString!R2));
Parameters
| Name | Description |
|---|---|
| sink | an output range |
| subject | the array to scan |
| from | the item to replace |
| to | the item to replace all instances of from with |
Returns
If sink isn't defined, a new array without changing the
contents of subject, or the original array if no match
is found.
See Also
substitute for a lazy replace.
Example
writeln("Hello Wörld" .replace("o Wö", "o Wo")); // "Hello World"
writeln("Hello Wörld" .replace("l", "h")); // "Hehho Wörhd"
Example
auto arr = [1, 2, 3, 4, 5];
auto from = [2, 3];
auto to = [4, 6];
auto sink = appender!(int[])();
replaceInto(sink, arr, from, to);
writeln(sink .data); // [1, 4, 6, 4, 5]
Authors
Andrei Alexandrescu and Jonathan M Davis
License
Copyright © 1999-2018 by the D Language Foundation | Page generated by ddox.