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Function `std.algorithm.searching.startsWith`

Checks whether the given input range starts with (one of) the given needle(s) or, if no needles are given, if its front element fulfils predicate pred.


						
				uint startsWith(alias pred, Range, Needles...)
				(
				

				  Range doesThisStart,
				

				  Needles withOneOfThese
				

				)
				

				if (isInputRange!Range && (Needles.length > 1) && is(typeof(.startsWith!pred(doesThisStart, withOneOfThese[0])) : bool) && is(typeof(.startsWith!pred(doesThisStart, withOneOfThese[1..__dollar])) : uint));
				

				

				bool startsWith(alias pred, R1, R2)
				(
				

				  R1 doesThisStart,
				

				  R2 withThis
				

				)
				

				if (isInputRange!R1 && isInputRange!R2 && is(typeof(binaryFun!pred(doesThisStart.front, withThis.front)) : bool));
				

				

				bool startsWith(alias pred, R, E)
				(
				

				  R doesThisStart,
				

				  E withThis
				

				)
				

				if (isInputRange!R && is(typeof(binaryFun!pred(doesThisStart.front, withThis)) : bool));
				

				

				bool startsWith(alias pred, R)
				(
				

				  R doesThisStart
				

				)
				

				if (isInputRange!R && ifTestable!(typeof(doesThisStart.front), unaryFun!pred));

Parameters

Name	Description
pred	Predicate to use in comparing the elements of the haystack and the needle(s). Mandatory if no needles are given.
doesThisStart	The input range to check.
withOneOfThese	The needles against which the range is to be checked, which may be individual elements or input ranges of elements.
withThis	The single needle to check, which may be either a single element or an input range of elements.

Returns

0 if the needle(s) do not occur at the beginning of the given range; otherwise the position of the matching needle, that is, 1 if the range starts with withOneOfThese[0], 2 if it starts with withOneOfThese[1], and so on.

In the case where doesThisStart starts with multiple of the ranges or elements in withOneOfThese, then the shortest one matches (if there are two which match which are of the same length (e.g. "a" and 'a'), then the left-most of them in the argument list matches).

In the case when no needle parameters are given, return true iff front of doesThisStart fulfils predicate pred.

Example

import std.ascii : isAlpha;

assert("abc".startsWith!(a => a.isAlpha));
assert("abc".startsWith!isAlpha);
assert(!"1ab".startsWith!(a => a.isAlpha));
assert(!"".startsWith!(a => a.isAlpha));

import std.algorithm.comparison : among;
assert("abc".startsWith!(a => a.among('a', 'b') != 0));
assert(!"abc".startsWith!(a => a.among('b', 'c') != 0));

assert(startsWith("abc", ""));
assert(startsWith("abc", "a"));
assert(!startsWith("abc", "b"));
writeln(startsWith("abc", 'a', "b")); // 1
writeln(startsWith("abc", "b", "a")); // 2
writeln(startsWith("abc", "a", "a")); // 1
writeln(startsWith("abc", "ab", "a")); // 2
writeln(startsWith("abc", "x", "a", "b")); // 2
writeln(startsWith("abc", "x", "aa", "ab")); // 3
writeln(startsWith("abc", "x", "aaa", "sab")); // 0
writeln(startsWith("abc", "x", "aaa", "a", "sab")); // 3

import std.typecons : Tuple;
alias C = Tuple!(int, "x", int, "y");
assert(startsWith!"a.x == b"([ C(1,1), C(1,2), C(2,2) ], [1, 1]));
writeln(startsWith!"a.x == b"([C(1, 1), C(2, 1), C(2, 2)], [1, 1], [1, 2], [1, 3])); // 2

Authors

Andrei Alexandrescu

License

Boost License 1.0.