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Function std.string.assumeUTF
Assume the given array of integers arr
is a well-formed UTF string and
return it typed as a UTF string.
auto assumeUTF(T)
(
T[] arr
)
if (staticIndexOf!(immutable(T), immutable(ubyte), immutable(ushort), immutable(uint)) != -1);
ubyte
becomes char
, ushort
becomes wchar
and uint
becomes dchar
. Type qualifiers are preserved.
When compiled with debug mode, this function performs an extra check to make sure the return value is a valid Unicode string.
Parameters
Name | Description |
---|---|
arr | array of bytes, ubytes, shorts, ushorts, ints, or uints |
Returns
arr retyped as an array of chars, wchars, or dchars
Throws
In debug mode AssertError
, when the result is not a well-formed UTF string.
See Also
Example
string a = "Hölo World";
immutable(ubyte)[] b = a .representation;
string c = b .assumeUTF;
writeln(c); // "Hölo World"
Authors
Walter Bright, Andrei Alexandrescu, Jonathan M Davis, and David L. 'SpottedTiger' Davis
License
Copyright © 1999-2022 by the D Language Foundation | Page generated by ddox.