Menu
Search

API Documentation

version 2.104.0

overview

View source code
Display the source code in std/algorithm/setops.d from which this page was generated on github.
Report a bug
If you spot a problem with this page, click here to create a Bugzilla issue.
Improve this page
Quickly fork, edit online, and submit a pull request for this page. Requires a signed-in GitHub account. This works well for small changes. If you'd like to make larger changes you may want to consider using local clone.

std.algorithm.setops.SetIntersection/setIntersection - multiple declarations

Function setIntersection

Lazily computes the intersection of two or more input ranges ranges. The ranges are assumed to be sorted by less. The element types of the ranges must have a common type.

SetIntersection!(less,Rs) setIntersection(alias less, Rs...) (
  Rs ranges
)
if (Rs.length >= 2 && allSatisfy!(isInputRange, Rs) && !is(CommonType!(staticMap!(ElementType, Rs)) == void));

In the case of multisets, the range with the minimum number of occurences of a given element, propagates the number of occurences of this element to the resulting range.

Parameters

NameDescription
less Predicate the given ranges are sorted by.
ranges The ranges to compute the intersection for.

Returns

A range containing the intersection of the given ranges.

Example

import std.algorithm.comparison : equal;

// sets
int[] a = [ 1, 2, 4, 5, 7, 9 ];
int[] b = [ 0, 1, 2, 4, 7, 8 ];
int[] c = [ 0, 1, 4, 5, 7, 8 ];
assert(equal(setIntersection(a, a), a));
assert(equal(setIntersection(a, b), [1, 2, 4, 7]));
assert(equal(setIntersection(a, b, c), [1, 4, 7]));

// multisets
int[] d = [ 1, 1, 2, 2, 7, 7 ];
int[] e = [ 1, 1, 1, 7];
assert(equal(setIntersection(a, d), [1, 2, 7]));
assert(equal(setIntersection(d, e), [1, 1, 7]));

Struct SetIntersection

Lazily computes the intersection of two or more input ranges ranges. The ranges are assumed to be sorted by less. The element types of the ranges must have a common type.

struct SetIntersection(alias less, Rs...)
  
if (Rs.length >= 2 && allSatisfy!(isInputRange, Rs) && !is(CommonType!(staticMap!(ElementType, Rs)) == void));

In the case of multisets, the range with the minimum number of occurences of a given element, propagates the number of occurences of this element to the resulting range.

Constructors

NameDescription
this (input)

Properties

NameTypeDescription
empty[get] bool
front[get] ElementType
save[get] SetIntersection

Methods

NameDescription
popFront ()

Parameters

NameDescription
less Predicate the given ranges are sorted by.
ranges The ranges to compute the intersection for.

Returns

A range containing the intersection of the given ranges.

Example

import std.algorithm.comparison : equal;

// sets
int[] a = [ 1, 2, 4, 5, 7, 9 ];
int[] b = [ 0, 1, 2, 4, 7, 8 ];
int[] c = [ 0, 1, 4, 5, 7, 8 ];
assert(equal(setIntersection(a, a), a));
assert(equal(setIntersection(a, b), [1, 2, 4, 7]));
assert(equal(setIntersection(a, b, c), [1, 4, 7]));

// multisets
int[] d = [ 1, 1, 2, 2, 7, 7 ];
int[] e = [ 1, 1, 1, 7];
assert(equal(setIntersection(a, d), [1, 2, 7]));
assert(equal(setIntersection(d, e), [1, 1, 7]));

Authors

Andrei Alexandrescu

License

Boost License 1.0.