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						Function std.algorithm.mutation.moveSome
Calls move(a, b) for each element a in src and the corresponding
element b in tgt, in increasing order, stopping when either range has been
exhausted.
						
				Tuple!(InputRange1,InputRange2) moveSome(InputRange1, InputRange2)
				(
				
				  InputRange1 src,
				
				  InputRange2 tgt
				
				)
				
				if (isInputRange!InputRange1 && isInputRange!InputRange2 && is(typeof(move(src
				Parameters
| Name | Description | 
|---|---|
| src | An input range with movable elements. | 
| tgt | An input range with
        elements that elements from srccan be moved into. | 
Returns
The leftover portions of the two ranges after one or the other of the ranges have been exhausted.
Example
int[5] a = [ 1, 2, 3, 4, 5 ];
int[3] b;
assert(moveSome(a[], b[])[0] is a[3 .. $]);
writeln(a[0 .. 3]); // b
writeln(a); // [1, 2, 3, 4, 5]
Authors
License
					Copyright © 1999-2024 by the D Language Foundation | Page generated by ddox.