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version 2.108.0

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Function dmd.json.tryParseJsonField

Parse the given fieldName and return its corresponding JsonFieldFlags value.

JsonFieldFlags tryParseJsonField (
  const(char)* fieldName
);

Parameters

NameDescription
fieldName the field name to parse

Returns

JsonFieldFlags.none on error, otherwise the JsonFieldFlags value corresponding to the given fieldName.

Authors

Walter Bright

License

Boost License 1.0