Report a bug
If you spot a problem with this page, click here to create a Bugzilla issue.
Improve this page
Quickly fork, edit online, and submit a pull request for this page. Requires a signed-in GitHub account. This works well for small changes. If you'd like to make larger changes you may want to consider using a local clone.

Type Qualifiers

Type qualifiers modify a type by applying a TypeCtor. TypeCtors are: const, immutable, shared, and inout. Each applies transitively to all subtypes.

Const and Immutable

When examining a data structure or interface, it is very helpful to be able to easily tell which data can be expected to not change, which data might change, and who may change that data. This is done with the aid of the language typing system. Data can be marked as const or immutable, with the default being changeable (or mutable).

immutable applies to data that cannot change. Immutable data values, once constructed, remain the same for the duration of the program's execution. Immutable data can be placed in ROM (Read Only Memory) or in memory pages marked by the hardware as read only. Since immutable data does not change, it enables many opportunities for program optimization, and has applications in functional style programming.

const applies to data that cannot be changed by the const reference to that data. It may, however, be changed by another reference to that same data. Const finds applications in passing data through interfaces that promise not to modify them.

Both immutable and const are transitive, which means that any data reachable through an immutable reference is also immutable, and likewise for const.

Immutable Storage Class

The simplest immutable declarations use it as a storage class. It can be used to declare manifest constants.

immutable int x = 3;  // x is set to 3
x = 4;        // error, x is immutable
char[x] s;    // s is an array of 3 chars

The type can be inferred from the initializer:

immutable y = 4; // y is of type int
y = 5;           // error, y is immutable

If the initializer is not present, the immutable can be initialized from the corresponding constructor:

immutable int z;
void test()
    z = 3; // error, z is immutable
static this()
    z = 3; // ok, can set immutable that doesn't
           // have static initializer

The initializer for a non-local immutable declaration must be evaluatable at compile time:

int foo(int f) { return f * 3; }
int i = 5;
immutable x = 3 * 4;      // ok, 12
immutable y = i + 1;      // error, cannot evaluate at compile time
immutable z = foo(2) + 1; // ok, foo(2) can be evaluated at compile time, 7

The initializer for a non-static local immutable declaration is evaluated at run time:

int foo(int f)
    immutable x = f + 1;  // evaluated at run time
    x = 3;                // error, x is immutable

Because immutable is transitive, data referred to by an immutable is also immutable:

immutable char[] s = "foo";
s[0] = 'a';  // error, s refers to immutable data
s = "bar";   // error, s is immutable

Immutable declarations can appear as lvalues, i.e. they can have their address taken, and occupy storage.

Const Storage Class

A const declaration is exactly like an immutable declaration, with the following differences:

Immutable Type

Data that will never change its value can be typed as immutable. The immutable keyword can be used as a type qualifier:

immutable(char)[] s = "hello";

The immutable applies to the type within the following parentheses. So, while s can be assigned new values, the contents of s[] cannot be:

s[0] = 'b';  // error, s[] is immutable
s = null;    // ok, s itself is not immutable

Immutability is transitive, meaning it applies to anything that can be referenced from the immutable type:

immutable(char*)** p = ...;
p = ...;        // ok, p is not immutable
*p = ...;       // ok, *p is not immutable
**p = ...;      // error, **p is immutable
***p = ...;     // error, ***p is immutable

Immutable used as a storage class is equivalent to using immutable as a type qualifier for the entire type of a declaration:

immutable int x = 3;   // x is typed as immutable(int)
immutable(int) y = 3;  // y is immutable

Creating Immutable Data

The first way is to use a literal that is already immutable, such as string literals. String literals are always immutable.

auto s = "hello";   // s is immutable(char)[5]
char[] p = "world"; // error, cannot implicitly convert immutable
                    // to mutable

The second way is to cast data to immutable. When doing so, it is up to the programmer to ensure that any mutable references to the same data are not used to modify the data after the cast.

char[] s = ['a'];
s[0] = 'b'; // ok
immutable(char)[] p = cast(immutable)s; // ok, if data is not mutated
                                        // through s anymore
s[0] = 'c'; // undefined behavior
immutable(char)[] q = cast(immutable)s.dup; // always ok, unique reference

char[][] s2 = [['a', 'b'], ['c', 'd']];
immutable(char[][]) p2 = cast(immutable)s2.dup; // dangerous, only the first
                                                // level of elements is unique
s2[0] = ['x', 'y']; // ok, doesn't affect p2
s2[1][0] = 'z'; // undefined behavior
immutable(char[][]) q2 = [s2[0].dup, s2[1].dup]; // always ok, unique references

The .idup property is a convenient way to create an immutable copy of an array:

auto p = s.idup;
p[0] = ...;       // error, p[] is immutable

Removing Immutable or Const with a Cast

An immutable or const type qualifier can be removed with a cast:

immutable int* p = ...;
int* q = cast(int*)p;

This does not mean, however, that one can change the data:

*q = 3; // allowed by compiler, but result is undefined behavior

The ability to cast away immutable-correctness is necessary in some cases where the static typing is incorrect and not fixable, such as when referencing code in a library one cannot change. Casting is, as always, a blunt and effective instrument, and when using it to cast away immutable-correctness, one must assume the responsibility to ensure the immutability of the data, as the compiler will no longer be able to statically do so.

Undefined Behavior: casting away a const qualifier and then mutating it, even when the referenced data is mutable. This is so that compilers and programmers can make assumptions based on const alone. For example, here it may be assumed that f does not alter x:
void f(const int* a);
void main()
    int x = 1;
    assert(x == 1); // guaranteed to hold

Immutable Member Functions

Immutable member functions are guaranteed that the object and anything referred to by the this reference is immutable. They are declared as:

struct S
    int x;

    void foo() immutable
        x = 4;      // error, x is immutable
        this.x = 4; // error, x is immutable

Note that using immutable on the left hand side of a method does not apply to the return type:

struct S
    immutable int[] bar()  // bar is still immutable, return type is not!

To make the return type immutable, surround it with parentheses:

struct S
    immutable(int[]) bar()  // bar is now mutable, return type is immutable.

To make both the return type and the method immutable, write:

struct S
    immutable(int[]) bar() immutable

Const Type

Const types are like immutable types, except that const forms a read-only view of data. Other aliases to that same data may change it at any time.

Const Member Functions

Const member functions are functions that are not allowed to change any part of the object through the member function's this reference.


Functions that differ only in whether the parameters are mutable, const or immutable, and have corresponding mutable, const or immutable return types, can be combined into one function using the inout type constructor. Consider the following overload set:

int[] slice(int[] a, int x, int y) { return a[x .. y]; }

const(int)[] slice(const(int)[] a, int x, int y) { return a[x .. y]; }

immutable(int)[] slice(immutable(int)[] a, int x, int y) { return a[x .. y]; }

The code generated by each of these functions is identical. The inout type constructor can combine them into one function:

inout(int)[] slice(inout(int)[] a, int x, int y) { return a[x .. y]; }

The inout keyword forms a wildcard that stands in for mutable, const, immutable, inout, or inout const. When calling the function, the inout state of the return type is changed to match that of the argument type passed to the inout parameter.

inout can also be used as a type constructor inside a function that has a parameter declared with inout. The inout state of a type declared with inout is changed to match that of the argument type passed to the inout parameter:

inout(int)[] asymmetric(inout(int)[] input_data)
    inout(int)[] r = input_data;
    while (r.length > 1 && r[0] == r[$-1])
        r = r[1..$-1];
    return r;

Inout types can be implicitly converted to const or inout const, but to nothing else. Other types cannot be implicitly converted to inout. Casting to or from inout is not allowed in @safe functions.

void f(inout int* ptr)
    const int* p = ptr;
    int* q = ptr; // error
    immutable int* r = ptr; // error

Matching an inout Parameter

A set of arguments to a function with inout parameters is considered a match if any inout argument types match exactly, or:

  1. No argument types are composed of inout types.
  2. A mutable, const or immutable argument type can be matched against each corresponding parameter inout type.

If such a match occurs, inout is considered the common qualifier of the matched qualifiers. If more than two parameters exist, the common qualifier calculation is recursively applied.

Common qualifier of the two type qualifiers
mutableconstimmutableinoutinout const
mutable (= m)mcccc
const (= c)ccccc
immutable (= i)cciwcwc
inout (= w)ccwcwwc
inout const (= wc)ccwcwcwc

The inout in the return type is then rewritten to match the inout qualifiers:

int[] ma;
const(int)[] ca;
immutable(int)[] ia;

inout(int)[] foo(inout(int)[] a) { return a; }
void test1()
    // inout matches to mutable, so inout(int)[] is
    // rewritten to int[]
    int[] x = foo(ma);

    // inout matches to const, so inout(int)[] is
    // rewritten to const(int)[]
    const(int)[] y = foo(ca);

    // inout matches to immutable, so inout(int)[] is
    // rewritten to immutable(int)[]
    immutable(int)[] z = foo(ia);

inout(const(int))[] bar(inout(int)[] a) { return a; }
void test2()
    // inout matches to mutable, so inout(const(int))[] is
    // rewritten to const(int)[]
    const(int)[] x = bar(ma);

    // inout matches to const, so inout(const(int))[] is
    // rewritten to const(int)[]
    const(int)[] y = bar(ca);

    // inout matches to immutable, so inout(int)[] is
    // rewritten to immutable(int)[]
    immutable(int)[] z = bar(ia);

Note: Shared types cannot be matched with inout.

Combining Qualifiers

More than one qualifier may apply to a type. The order of application is irrelevant, for example given an unqualified type T, const shared T and shared const T are the same type. For that reason, this document depicts qualifier combinations without parentheses unless necessary and in alphabetic order.

Applying a qualifier to a type that already has that qualifier is legal but has no effect, e.g. given an unqualified type T, shared(const shared T) yields the type const shared T.

Applying the immutable qualifier to any type (qualified or not) results in immutable T. Applying any qualifier to immutable T results in immutable T. This makes immutable a fixed point of qualifier combinations and makes types such as const(immutable(shared T)) impossible to create.

Assuming T is an unqualified type, the graph below illustrates how qualifiers combine (combinations with immutable are omitted). For each node, applying the qualifier labeling the edge leads to the resulting type.

Qualifier combination rules

Implicit Qualifier Conversions

Values that have no mutable indirections (including structs that don't contain any field with mutable indirections) can be implicitly converted across mutable, const, immutable, const shared, inout and inout shared.

References to qualified objects can be implicitly converted according to the following rules:

Qualifier conversion rules

In the graph above, any directed path is a legal implicit conversion. No other qualifier combinations than the ones shown is valid. If a directed path exists between two sets of qualifiers, the types thus qualified are called qualifier-convertible. The same information is shown below in tabular format:

Implicit Conversion of Reference Types
from/tomutableconstsharedconst sharedinoutconst inoutinout sharedconst inout sharedimmutable
const inout
const shared
const inout shared
inout shared

If an implicit conversion is disallowed by the table, an Expression may be converted if:

An expression may be converted from mutable or shared to immutable if the expression is unique and all expressions it transitively refers to are either unique or immutable.

An expression may be converted from mutable to shared if the expression is unique and all expressions it transitively refers to are either unique, immutable, or shared.

An expression may be converted from immutable to mutable if the expression is unique.

An expression may be converted from shared to mutable if the expression is unique.

A Unique Expression is one for which there are no other references to the value of the expression and all expressions it transitively refers to are either also unique or are immutable. For example:

void main()
    immutable int** p = new int*(null); // ok, unique

    int x;
    immutable int** q = new int*(&x); // error, there may be other references to x

    immutable int y;
    immutable int** r = new immutable(int)*(&y); // ok, y is immutable

Otherwise, a CastExpression can be used to force a conversion when an implicit version is disallowed, but this cannot be done in @safe code, and the correctness of it must be verified by the user.